Terminal velocity

For other uses, see Terminal velocity (disambiguation).

An object reaches terminal velocity when the downward force of gravity (F_g)equals the upward force of drag (F_d). The net force on the body is then zero, and the result is that the velocity of the object remains constant.

A free falling object achieves its terminal velocity when the downward force of gravity (F_g)equals the upward force of drag (F_d). This causes the net force on the object to be zero, resulting in an acceleration of zero. Mathematically an object asymptotically approaches and can never reach its terminal velocity.

As the object accelerates (usually downwards due to gravity), the drag force acting on the object increases. At a particular speed, the drag force produced will equal the object's weight $(m g)$ . Eventually, it plummets at a constant speed called terminal velocity (also called settling velocity). Terminal velocity varies directly with the ratio of drag to weight. More drag means a lower terminal velocity, while increased weight means a higher terminal velocity. An object moving downward at greater than terminal velocity (for example because it was affected by a downward force or it fell from a thinner part of the atmosphere or it changed shape) will slow until it reaches terminal velocity.

1 Examples
- 1.1 Velocity of a falling object after a given time
2 Terminal velocity in the presence of buoyancy force
- 2.1 Terminal velocity in creeping flow
- 2.2 Applications
3 Also see
4 References
5 External links

Examples

For example, the terminal velocity of a skydiver in a free-fall position with a semi-closed parachute is about 195 km/h (120 mph or 55m/s)^[1]. Parachuting, also known as skydiving is where a person jumps from enough height so that he can deploy a fabric Parachute and land safely Free fall is motion with no Acceleration other than that provided by Gravity. A parachute is a device used to slow the motion of an object through an atmosphere by creating drag. (For the South African airport with IATA code "KMH" see Johan Pienaar Airport. This velocity is the asymptotic limiting value of the acceleration process, since the effective forces on the body more and more closely balance each other as the terminal velocity is approached. An asymptote of a real-valued function y=f(x is a curve which describes the behavior of f as either x or y goes to infinity In this example, a speed of 50% of terminal velocity is reached after only about 3 seconds, while it takes 8 seconds to reach 90%, 15 seconds to reach 99% and so on.

Higher speeds can be attained if the skydiver pulls in his limbs (see also freeflying). Freeflying is a Skydiving discipline which began circa 1994 by a group of skydivers who wanted to experiment with non-traditional forms of flight In this case, the terminal velocity increases to about 320 km/h (200 mph or 89 m/s)^[1], which is also the terminal velocity of the peregrine falcon diving down on its prey^[2], and a typical 150 g bullet travelling in the downward vertical direction which is returning to earth having been fired upwards or perhaps just dropped from a tower, which has a terminal velocity of about 300 feet per second (90 m/s) according to a 1920 U. The Peregrine Falcon ( Falco peregrinus) also known simply as the Peregrine, and historically as the "Duck Hawk" in North America is a S. Army Ordnance study^[3].

Competition speed skydivers fly in the head down position reaching even higher speeds. The current world record is 614 mph (988 km/h) by Joseph Kittinger, set at high altitude where the lesser density of the atmosphere decreased drag^[1]. Joseph William Kittinger II (born July 27 1928 is a former pilot and career Military officer in the United States Air Force.

An object falling on Earth will fall 9. 81 meters per second faster every second (9. 81 m/s²). The reason an object reaches a terminal velocity is that the drag force resisting motion is directly proportional to the square of its speed. At low speeds, the drag is much less than the gravitational force and so the object accelerates. As it accelerates, the drag increases, until it equals the weight. Drag also depends on the projected area. This is why things with a large projected area, such as parachutes, have a lower terminal velocity than small objects such as cannon balls.

Mathematically, terminal velocity, without considering the buoyancy effects, is given by

$V_t= \sqrt{\frac{2mg}{\rho A C_d }}$ ^{(see derivation)}

where

V t

= terminal velocity,

m

= mass of the falling object,

g

= gravitational acceleration,

C d

= drag coefficient,

ρ

= density of the fluid through which the object is falling, and

A

= projected area of the object. In Physics, buoyancy ( BrE IPA: /ˈbɔɪənsi/ is the upward Force on an object produced by the surrounding liquid or gas in which it is Derivations from Terminal velocity. Derivation of Terminal Velocity A falling object experiences two forces gravitational force and a large-velocity drag force In Physics, gravitational acceleration is the Acceleration of an object caused by the Force of gravity from another object The drag coefficient ( Cd, Cx or Cw) is a Dimensionless quantity that describes how streamlined an The density of a material is defined as its Mass per unit Volume: \rho = \frac{m}{V} Different materials usually have different

On Earth, the terminal velocity of an object changes due to the properties of the fluid, mass and the projected area of the object.

This equation is derived from the drag equation by setting drag equal to mg, the gravitational force on the object. In Fluid dynamics, the drag equation is a practical formula used to calculate the force of drag experienced by an object due to a Fluid that it is moving

Density increases with decreasing altitude, ca. 1% per 80 m (see barometric formula). The barometric formula, sometimes called the exponential atmosphere or Isothermal Atmosphere, is a Formula used Therefore, for every 160 m of falling, the terminal velocity decreases 1%. After reaching the local terminal velocity, while continuing the fall, speed decreases to change with the local terminal velocity.

Velocity of a falling object after a given time

Mathematically, defining down to be positive, the net force acting on an object falling near the surface of Earth is (according to the drag equation),

$F_{net}=m\mathbf{a}=m g - {1 \over 2} \rho v^2 A C_d$ . In Fluid dynamics, the drag equation is a practical formula used to calculate the force of drag experienced by an object due to a Fluid that it is moving

To make the derivation of the formula more practical a substitution is made with $k={1 \over 2} \rho A C_d$ .

Dividing through by $m$ gives,

$\mathbf{a}=g - \frac{kv^2}{m}$

where $a$ = the acceleration of the object.

Since

$\mathbf{a}=\frac{dv}{dt}$

the following is true,

$\frac{dv}{dt}=g-\frac{kv^2}{m}$ .

Thus,

$dt=\frac{dv}{g-\frac{kv^2}{m}}$ .

Taking the integral of both sides yields,

$\int_0^t {dt}=\int_0^v \frac{dv}{g-\frac{kv^2}{m}}$ .

Factoring $g$ out of the denominator and making the substitution $a=\sqrt\frac{k}{mg}$ (not to be confused with acceleration) leads to,

$\int_0^t {dt}={1 \over g}\int_0^v \frac{dv}{1-a^2 v^2}$ .

Factoring the bottom,

$\int_0^t {dt}={1 \over g}\int_0^v \frac{dv}{(1+av)(1-av)}$ .

Partial fraction expansions tell us that,

$\frac{1}{(1+av)(1-av)}=\frac{A}{1+av}+\frac{B}{1-av}$ .

Multiplying by the denominator on the bottom gives,

$\qquad 1=A(1-av)+B(1+av)$ .

If $v = 0$ , then

$\qquad A+B=1$ .

Now let us suppose that $a v = 1$ , then

$\qquad 1=A(1-1)+B(1+1)=2B$ ,

and

$\qquad B={1 \over 2}$ .

Therefore, for the sum of $A$ and $B$ to be 1,

$\qquad A={1 \over 2}$ .

With these new expanded fractions,

$\int_0^t {dt}={1 \over g} \int_0^v \frac{1/2}{1+av}dv + {1 \over g} \int_0^v \frac{1/2}{1-av}dv$

We now want to evaluate both integrals on the left side. The first one is,

$\int \frac{1/2}{1+av}dv$ .

Making a substitution

$\qquad u=1+av$ ,

we find that,

$\qquad {du \over a}=dv$ ,

and thus,

$\int \frac{1/2}{1+av}dv={1 \over 2a}\int \frac{1}{u}du={\ln u \over 2a}+C={\ln(1+av) \over 2a}+C$ .

Now we want to evaluate the second part of the left hand side,

$\int \frac{1/2}{1-av}$ .

Making a substitution

$\qquad u=1-av$ ,

we find that

$\qquad -\frac{du}{a}=dv$ ,

and thus,

$\int \frac{1/2}{1-av}=-\frac{1}{2a} \int {1 \over u} du=-\frac{\ln u}{2a}+C=-\frac{\ln(1-av)}{2a}+C$ .

Putting these back into our original formula, we get,

$t-0={1 \over g}\left[{\ln(1+av) \over 2a}-\frac{\ln(1-av)}{2a} \right]_{v=0}^{v=v}+C={1 \over g} \left[{\ln \frac{1+av}{1-av} \over 2a} \right]_{v=0}^{v=v}+C$ ,

and thus,

$t={1 \over 2ag} \ln \frac{1+av}{1-av}-0+C$ .

Since $v = 0$ when $t = 0$ , we find that $C = 0$ . We also have a specially defined function, the inverse hyperbolic tangent that is defined such that,

$\frac{1}{2} \ln \frac{1+av}{1-av}=\operatorname{artanh}(av)$ .

So,

$t=\frac{\operatorname{artanh}(av)}{ag}$ .

Thus,

$\frac{1}{a}\tanh(tag)=v$ ,

and thus, substituting a back in,

$v=\sqrt{\frac{mg}{k}} \tanh \left(\sqrt{\frac{k}{mg}}gt\right)$

substituting and simplifying, assuming that g is positive (which it was defined to be), we arrive at the final equation,

$v=\sqrt\frac{2mg}{\rho A C_d} \tanh \left(t \sqrt{\frac{g \rho A C_d }{2m}}\right)$ .

Terminal velocity in the presence of buoyancy force

When the buoyancy effects are taken into account, an object falling through a fluid under its own weight can reach a terminal velocity (settling velocity) if the net force acting on the object becomes zero. When the terminal velocity is reached the weight of the object is exactly balanced by the upward buoyancy force and drag force. In Physics, buoyancy ( BrE IPA: /ˈbɔɪənsi/ is the upward Force on an object produced by the surrounding liquid or gas in which it is That is

$\quad (1) \qquad W = F_b + D$

where

W

= weight of the object,

F b

= buoyancy force acting on the object, and

D

= drag force acting on the object.

If the falling object is spherical in shape, the expression for the three forces are give below:

$\quad (2) \qquad W = \frac{\pi}{6} d^3 \rho_s g$

$\quad (3) \qquad F_b = \frac{\pi}{6} d^3 \rho g$

$\quad (4) \qquad D = C_d \frac{1}{2}\rho V^2 A$

Kinetic energy: mass times velocity squared divided by two

d =

diameter of the spherical object

g =

gravitational acceleration,

ρ =

density of the fluid,

ρ s =

density of the object,

A = π d 2 / 4 =

projected area of the sphere,

C d =

drag coefficient, and

V =

characteristic velocity (taken as terminal velocity,

V t

Substitution of equations (2-4) in equation (1) and solving for terminal velocity, $V t$ to yield the following expression

$\quad (5) \qquad V_t = \sqrt{\frac{4 g d}{3 C_d} \left( \frac{\rho_s - \rho}{\rho} \right)}$ .

Terminal velocity in creeping flow

Creeping flow past a sphere: streamlines, drag force F_d and force by gravity F_g.

For very slow motion of the fluid, the inertia forces of the fluid are negligible (assumption of massless fluid) in comparison to other forces. Such flows are called creeping flows and the condition to be satisfied for the flow to be creeping flows is the Reynolds number, $Re \ll 1$ . Stokes flow (named after George Gabriel Stokes) is a type of Fluid flow where advective inertial forces are small compared with viscous In Fluid mechanics and Heat transfer, the Reynolds number \mathrm{Re} is a Dimensionless number that gives a measure of the Ratio The equation of motion for creeping flow (simplified Navier-Stokes equation) is given by

$\nabla p = \mu \nabla^2 {\mathbf v}$

where

${\mathbf v}$ = velocity vector field

p

= pressure field

μ

= fluid viscosity

The analytical solution for the creeping flow around a sphere was first given by Stokes in 1851. The Navier–Stokes equations, named after Claude-Louis Navier and George Gabriel Stokes, describe the motion of viscous Fluid substances such Viscosity is a measure of the resistance of a Fluid which is being deformed by either Shear stress or Extensional stress. Sir George Gabriel Stokes 1st Baronet FRS ( 13 August 1819 &ndash 1 February 1903) was a mathematician and physicist From Stokes' solution, the drag force acting on the sphere can be obtained as

$\quad (6) \qquad D = 3\pi \mu d V \qquad \qquad \text{or} \qquad \qquad C_d = \frac{24}{Re}$

where the Reynold's number, $Re = \frac{\rho d V}{\mu}$ . The expression for the drag force given by equation (6) is called Stokes law. Stokes' law can refer to Stokes' law for friction force Stokes' law (sound attenuation law describing attenuation of sound in Newtonian liquids

When the value of $C d$ is substituted in the equation (5), we obtain the expression for terminal velocity of a spherical object moving under creeping flow conditions:

$V_t = \frac{g d^2}{18 \mu} \left(\rho_s - \rho \right).$

Applications

The creeping flow results can be applied in order to study the settling of sediment particles near the ocean bottom and the fall of moisture drops in the atmosphere. The principle is also applied in the falling sphere viscometer, an experimental device used to measure the viscosity of high viscous fluids. A viscometer (also called viscosimeter) is an instrument used to measure the Viscosity of a Fluid.

Also see

Stokes law

References

^ ^a ^b ^c Huang, Jian (1999). Stokes' law can refer to Stokes' law for friction force Stokes' law (sound attenuation law describing attenuation of sound in Newtonian liquids Speed of a Skydiver (Terminal Velocity). The Physics Factbook. Glenn Elert, Midwood High School, Brooklyn College.
^ All About the Peregrine Falcon. U. S. Fish and Wildlife Service (2007-12-20). Year 2007 ( MMVII) was a Common year starting on Monday of the Gregorian calendar in the 21st century. Events 69 - Vespasian, formerly a general under Nero, enters Rome to claim the title of Emperor.
^ The Ballistician (March 2001). Bullets in the Sky. W. Square Enterprises, 9826 Sagedale, Houston, Texas 77089.

External links

Terminal Velocity - NASA site

Dictionary

-noun

The speed at which an object in free-fall and not in a vacuum ceases to accelerate downwards because the force of gravity is equal and opposite to the drag force acting against it.

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Contents

Examples

Velocity of a falling object after a given time

Terminal velocity in the presence of buoyancy force

Terminal velocity in creeping flow

Applications

Also see

References

External links

Dictionary

terminal velocity

-noun